(t^2/3)+(10t1/3)+16=0

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Solution for (t^2/3)+(10t1/3)+16=0 equation: 


t in (-oo:+oo)

(t^2)/3+(10*t^1)/3+16 = 0

(t^2)/3+(10*t)/3+16 = 0

1/3*t^2+10/3*t+16 = 0

DELTA = (10/3)^2-(1/3*4*16)

DELTA = -92/9

DELTA < 0

t belongs to the empty set

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